# Line slope calculator 3x+y=3

**Straight line given by points A[0; 3] and B[1; 0]**

## Calculation:

**Slope-intercept form of line:**y = -3x+3

**Canonical form of the line equation:**3x+y-3 = 0

**Parametric form of the line equation:**

x = t

y = -3t+3 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 0.9487

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; -3)

**Normal vector: n =**(3; 1)

**Midpoint of the segment AB: M =**[0.5; 1.5]

**Perpendicular Bisector equation:**x-3y+4 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (1; 0) ; |OB| = 1**

**Scalar product OA .OB = 0**

**Angle ∠ AOB = 90° = 1.5708 rad**